These questions are the most
frequently asked in interviews
- To fetch ALTERNATE records from a table. (EVEN
NUMBERED)
Ans:select * from emp where rowid in (select decode
(mod(rownum,2),0,rowid,
null) from emp);
- To select ALTERNATE records from a table. (ODD NUMBERED)
(select decode(mod(rownum,2),0,null ,rowid) from emp);
- Find the 3rd MAX salary in the emp table.
Ans:select
distinct sal from emp e1 where 3 = (select count(distinct sal) from emp e2 where e1.sal <= e2.sal);
- Find the 3rd MIN salary in the emp table.
count(distinct sal) from emp
e2where e1.sal >= e2.sal);
- Select FIRST n records from a table.
Ans :select * from emp where rownum <= &n;
- Select LAST n records from a table
Ans :select *
from emp minus select * from emp where
rownum <= (select count(*) - &n from emp);
- List dept no., Dept name for all the departments in
which there are no employees in the department.
Ans select *
from dept where deptno not in
(select deptno from emp);
- alternate solution:
select * from dept a where not exists (select * from emp b where
a.deptno = b.deptno);
Ans Altertnate
solution:
select
empno,ename,b.deptno,dname from emp
a, dept b
where a.deptno(+) = b.deptno and empno is null;
- How to get 3 Max salaries ?
Ans :select distinct sal from emp a where 3 >=
(select
count(distinct sal) from emp b where a.sal <= b.sal) order by a.sal desc;
- How to get 3 Min salaries ?
Ans :select distinct sal from emp a
where 3 >=
(select count(distinct sal) from emp b where a.sal >= b.sal);
- How to get nth max salaries ?
Ans :select
distinct hiredate from emp a where &n =
(select count(distinct sal) from emp b where a.sal >= b.sal);
- Select DISTINCT RECORDS from emp table.
Ans :select * from emp a where
rowid =
(select max(rowid) from emp b where a.empno=b.empno);
- How to delete duplicate rows in a table?
Ans :delete from emp a where rowid !=
(select max(rowid) from emp b
where a.empno=b.empno);
- Count of number of employees in department wise.
Ans :select count(EMPNO), b.deptno, dname from emp a, dept b
where a.deptno(+)=b.deptno group by b.deptno,dname;
- Suppose there is annual salary information provided by
emp table. How to fetch monthly salary of each and every employee?
Ans :
- select ename,sal/12 as monthlysal from emp;
- Select all record from emp table where deptno =10 or
40.
- select * from emp where deptno=30 or deptno=10;
- Select all record from emp table where deptno=30 and
sal>1500.
- select * from emp where deptno=30 and sal>1500;
- Select all
record from emp where job not in
SALESMAN or CLERK.
Ans :select * from emp where job not in ('SALESMAN','CLERK');
- Select all record from emp where ename in
'BLAKE','SCOTT','KING'and'FORD'.
Ans :select * from emp where ename
in('JONES','BLAKE','SCOTT','KING','FORD');
- Select all records where ename starts with ‘S’ and its
lenth is 6 char.
Ans : select *
from emp where ename like'S____';
- Select all records where ename may be any no of character but it should end with ‘R’.
Ans : select *
from emp where ename like'%R';
- Count MGR and
their salary in emp table.
Ans : select count(MGR),count(sal)
from emp;
- In emp table add comm+sal as total sal .
Ans : select
ename,(sal+nvl(comm,0)) as totalsal from emp;
- Select any
salary <3000 from emp table.
Ans :select * from emp where
sal> any(select sal from emp where sal<3000);
- Select all
salary <3000 from emp table.
Ans select * from emp where
sal> all(select sal from emp where sal<3000);
- Select all the employee
group by deptno and sal in descending order.
Ans select ename,deptno,sal from emp order by deptno,sal desc;
- How can I create an empty table emp1 with same
structure as emp?
Ans Create table emp1 as select * from emp where 1=2;
- How to retrive record where sal between 1000 to 2000?
Ans Select * from emp where sal>=1000 And sal<2000
- Select all records where dept no of both emp and dept
table matches.
Ans :select * from emp where exists(select * from dept
where
emp.deptno=dept.deptno)
- If there are two tables emp1 and emp2, and both have
common record. How can I fetch all the recods but common records only
once?
Ans :(Select * from emp) Union (Select * from emp1)
- How to fetch only common records from two tables emp
and emp1?
Ans :(Select * from emp) Intersect (Select * from emp1)
- How can I retrive all records of emp1 those should not
present in emp2?
Ans (Select * from emp) Minus (Select * from emp1)
- Count the totalsa
deptno wise where more than 2 employees exist.
Ans :
SELECT deptno, sum(sal)
As totalsal
FROM emp
GROUP BY deptno
HAVING COUNT(empno) > 2
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